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php filter_var email error


i use he filter_var php function to validate email address when a user sign up to my site



so i use this code form the post:




$email = filter_var($_POST['email'], FILTER_VALIDATE_EMAIL);



then later i do:




if(!$email) {
// return to the form
}
else {
// send registration info
}



now when i var_dump($email)



output:




string(23) "user."name"@example.com"



i would like to know why this not return false, i think the double quotes are not acceptable why PHP say it's valid?


Source: Tips4allCCNA FINAL EXAM

Comments

  1. It is a valid email address :


    A quoted string may exist as a dot separated entity within the
    local-part or it may exist when the outermost quotes are the outermost
    chars of the local-part (e.g. abc."defghi".xyz@example.com or
    "abcdefghixyz"@example.com are allowed. abc"defghi"xyz@example.com is
    not; neither is abc\"def\"ghi@example.com). Quoted strings and
    characters however, are not commonly used. RFC 5321 also warns that "a
    host that expects to receive mail SHOULD avoid defining mailboxes
    where the Local-part requires (or uses) the Quoted-string form" (sic).

    ReplyDelete
  2. I had the same problem (see ladaraider on why it's valid) and here's how I fixed it:

    filter_var($email, FILTER_SANITIZE_EMAIL);


    eg:

    $email = 'user."name"@example.com';
    $email = filter_var($email, FILTER_SANITIZE_EMAIL);


    will output:

    string(21) "user.name@example.com"


    Then you can validate the email using your validation.

    you can get more information on the php site

    ReplyDelete

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