Skip to main content

#define in Java


I'm beginning to program in Java and I'm wondering if the equivalent to the C++ #define exists.



A quick search of google says that it doesn't, but could anyone tell me if something similar exists in Java? I'm trying to make my code more readable.



Instead of myArray[0] I want to be able to write myArray[PROTEINS] for example.


Source: Tips4all

Comments

  1. No, because there's no precompiler.

    However, Hotspot is quite amazingly good at optimising where possible, so in your case you could achieve the same thing as follows:

    class MyClass
    {
    private static final int PROTEINS = 0;

    ...

    MyArray[] foo = new MyArray[PROTEINS];

    }


    The compiler will notice that PROTEINS can never, ever change and so will inline it which is more or less what you want.

    Note that the access modifier on the constant is unimportant here, so it could be public or protected instead of private, if you wanted to reuse the same constant across multiple classes.

    ReplyDelete
  2. Comment space too small, so here is some more information for you on the use of static final. As I said in my comment to the Andrzej's answer, only primitive and String are compiled directly into the code as literals. To demonstrate this, try the following:

    You can see this in action by creating three classes (in separate files):

    public class DisplayValue {
    private String value;

    public DisplayValue(String value) {
    this.value = value;
    }

    public String toString() {
    return value;
    }
    }

    public class Constants {
    public static final int INT_VALUE = 0;
    public static final DisplayValue VALUE = new DisplayValue("A");
    }

    public class Test {
    public static void main(String[] args) {
    System.out.println("Int = " + Constants.INT_VALUE);
    System.out.println("Value = " + Constants.VALUE);
    }
    }


    Compile these and run Test, which prints:


    Int = 0
    Value = A


    Now, change Constants to have a different value for each and just compile class Constants. When you execute Test again (without recompiling the class file) it still prints the old value for INT_VALUE but not VALUE. For example:

    public class Constants {
    public static final int INT_VALUE = 2;
    public static final DisplayValue VALUE = new DisplayValue("X");
    }


    Run Test without recompiling Test.java:


    Int = 0
    Value = X


    Note that any other type used with static final is kept as a reference.

    Similar to C/C++ #if/#endif, a constant literal or one defined through static final with primitives, used in a regular Java if condition and evaluates to false will cause the compiler to strip the byte code for the statements within the if block (they will not be generated).

    private static final boolean DEBUG = false;

    if (DEBUG) {
    ...code here...
    }


    The code at "...code here..." would not be compiled into the byte code. But if you changed DEBUG to true then it would be.

    ReplyDelete
  3. static final int PROTEINS = 1
    ...
    myArray[PROTEINS]


    You'd normalput "constants" in the class itself. And do note that a compiler is allowed to optimize references to it away, so don't change it unless you recompile all the using classes.

    class Foo {
    public static final int SIZE = 5;

    public static int[] arr = new int[SIZE];
    }
    class Bar {
    int last = arr[Foo.SIZE - 1];
    }


    edit cycle... SIZE=4. Also compile Bar because you compiler may have just written "4" in the last compilation cycle!

    ReplyDelete
  4. Java doesn't have a general purpose define preprocessor directive.

    In the case of constants, it is recommended to declare them as static finals, like in

    private static final int PROTEINS = 100;


    Such declarations would be inlined by the compilers (if the value is a compile-time constant).

    Please note also that public static final constant fields are part of the public interface and their values shouldn't change (as the compiler inlines them). If you do change the value, you would need to recompile all the sources that referenced that constant field.

    ReplyDelete

Post a Comment

Popular posts from this blog

Why is this Javascript much *slower* than its jQuery equivalent?

I have a HTML list of about 500 items and a "filter" box above it. I started by using jQuery to filter the list when I typed a letter (timing code added later): $('#filter').keyup( function() { var jqStart = (new Date).getTime(); var search = $(this).val().toLowerCase(); var $list = $('ul.ablist > li'); $list.each( function() { if ( $(this).text().toLowerCase().indexOf(search) === -1 ) $(this).hide(); else $(this).show(); } ); console.log('Time: ' + ((new Date).getTime() - jqStart)); } ); However, there was a couple of seconds delay after typing each letter (particularly the first letter). So I thought it may be slightly quicker if I used plain Javascript (I read recently that jQuery's each function is particularly slow). Here's my JS equivalent: document.getElementById('filter').addEventListener( 'keyup', function () { var jsStart = (new Date).getTime()...

Is it possible to have IF statement in an Echo statement in PHP

Thanks in advance. I did look at the other questions/answers that were similar and didn't find exactly what I was looking for. I'm trying to do this, am I on the right path? echo " <div id='tabs-".$match."'> <textarea id='".$match."' name='".$match."'>". if ($COLUMN_NAME === $match) { echo $FIELD_WITH_COLUMN_NAME; } else { } ."</textarea> <script type='text/javascript'> CKEDITOR.replace( '".$match."' ); </script> </div>"; I am getting the following error message in the browser: Parse error: syntax error, unexpected T_IF Please let me know if this is the right way to go about nesting an IF statement inside an echo. Thank you.