1 . Which security protocol or measure would provide the greatest protection for a wireless LAN? WPA2 cloaking SSIDs shared WEP key MAC address filtering 2 . Refer to the exhibit. All trunk links are operational and all VLANs are allowed on all trunk links. An ARP request is sent by computer 5. Which device or devices will receive this message? only computer 4 computer 3 and RTR-A computer 4 and RTR-A computer 1, computer 2, computer 4, and RTR-A computer 1, computer 2, computer 3, computer 4, and RTR-A all of the computers and the router 3 . Refer to the exhibit. Hosts A and B, connected to hub HB1, attempt to transmit a frame at the same time but a collision occurs. Which hosts will receive the collision jamming signal? only hosts A and B only hosts A, B, and C only hosts A, B, C, and D only hosts A, B, C, and E 4 . Refer to the exhibit. Router RA receives a packet with a source address of 192.168.1.65 and a destination address of 192.168.1.161...
Java is confusing because everything is passed by value. However for a parameter of reference type (i.e. not a parameter of primitive type) it is the reference itself which is passed by value, hence it appears to be pass-by-reference (and people often claim that it is). This is not the case, as shown by the following:
ReplyDeleteObject o = "Hello";
mutate(o)
System.out.println(o);
private void mutate(Object o) { o = "Goodbye"; } //NOT THE SAME o!
Will print Hello to the console. The options if you wanted the above code to print Goodbye are to use an explicit reference as follows:
AtomicReference<Object> ref = new AtomicReference<Object>("Hello");
mutate(ref);
System.out.println(ref.get()); //Goodbye!
private void mutate(AtomicReference<Object> ref) { ref.set("Goodbye"); }
Can I pass parameters by reference in
ReplyDeleteJava?
No.
Why ? Java has only one mode of passing arguments to methods: by value.
Note:
For primitives this is easy to understand: you get a copy of the value.
For all other you get a copy of the reference and this is called also passing by value.
It is all in this picture:
In Java there is nothing at language level similar to ref. In Java there is only passing by value semantic
ReplyDeleteFor the sake of curiosity you can implement a ref-like semantic in Java simply wrapping your objects in a mutable class:
public class Ref<T> {
private T value;
public Ref(T value) {
this.value = value;
}
public T get() {
return value;
}
public void set(T anotherValue) {
value = anotherValue;
}
@Override
public String toString() {
return value.toString();
}
@Override
public boolean equals(Object obj) {
return value.equals(obj);
}
@Override
public int hashCode() {
return value.hashCode();
}
}
testcase:
public void changeRef(Ref<String> ref) {
ref.set("bbb");
}
// ...
Ref<String> ref = new Ref<String>("aaa");
changeRef(ref);
System.out.println(ref); // prints "bbb"
From James Gosling in "The Java Programming Language":
ReplyDelete"...There is exactly one parameter passing mode in Java - pass by value - and that keeps things simple.
.."
I don't think you can. Your best option might be to encapsulate the thing you want to pass "by ref" onto another class instance, and pass the (outer) class's reference (by value). If you see what I mean...
ReplyDeletei.e. your method changes the internal state of the object it is passed, which is then visible to the caller.
See my article, "Java is Pass-By-Value, Dammit!" for a very detailed explanation of how Java passes parameters.
ReplyDeleteJava is always pass by value.
ReplyDeleteWhen you pass a primitive it's a copy of the value, when you pass an object it's a copy of the reference pointer.
Java is neither pass by reference nor by value.
ReplyDeleteSee an example here