I need to pass a function as a parameter to another function and then call the passed function from withing the function...This is probably easier for me to explain in code..I basically want to do something like this:
function ($functionToBeCalled)
{
call($functionToBeCalled,additional_params);
}
Is there a way to do that.. I am using PHP 4.3.9
Thanks!
Source: Tips4all
I think you are looking for call_user_func.
ReplyDeleteAn example from the PHP Manual:
<?php
function barber($type) {
echo "You wanted a $type haircut, no problem";
}
call_user_func('barber', "mushroom");
call_user_func('barber', "shave");
?>
function foo($function) {
ReplyDelete$function(" World");
}
function bar($params) {
echo "Hello".$params;
}
$variable = 'bar';
foo($variable);
Additionally, you can do it this way. See variable functions.
In php this is very simple.
ReplyDelete<?php
function here() {
print 'here';
}
function dynamo($name) {
$name();
}
//Will work
dynamo('here');
//Will fail
dynamo('not_here');
You could also use call_user_func_array() it allows you to pass an array of parameters as the second parameter so you don't have to know exactly how many variables you're passing.
ReplyDelete