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hiding and showing radio button and dropdown based on values





<select name="drop1" id='drop1'>

<option value="" selected="selected"></option>

<option value="data1">Data1</option>

<option value="data2L">Data2</option>



<select name="drop2" id='drop2'>

<option value="" selected="selected"></option>

<option value="data3">Data3</option>

<option value="data4">Data4</option>







When I select data1 and data3 from the two drop downs i need to display another dropdown below:







<div id="show_drop">

<select name="drop3" id='drop3'>

<option value="" selected="selected"></option>

<option value="data5">Data5</option>

</div>







else display radio button:







<div id="rbutton">

<input type="radio" name="yes" value="Yes" />Yes

<input type="radio" name="no" value="No" />No

</div>







I have tried the following code which works fine if i change only one drop down value. I am not sure of the synatx comparing 2 drop down values and then hiding radio button or the dropdown.







$(document).ready(function() {

$("#rbutton").hide();

$("#drop2").change(function() {

if ($("#drop2").val() == 'data2')

$("rbutton").show("fast");

else

$("#rbutton").hide("fast");

});

});




Comments

  1. Have a look here and see if this is what you had in mind: http://jsfiddle.net/ZtJVM/

    ReplyDelete
  2. $("#drop1,#drop2").change(function() {

    if ($("#drop1").val() == 'data1' && $("#drop2").val() == 'data2')
    $("rbutton").show("fast");
    else
    $("#rbutton").hide("fast");

    });


    is triggered when either select changed, checkes both values

    ReplyDelete

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