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Why isn"t spring using my constructor to init this bean (Map parameter)

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By User



I have a spring beans configuration file where I define the following jackson classes as spring beans.








For some reason on run-time the filterProvider bean is instantiated without the map argument.


You can see from the docs that the SimpleFilterProvider does have such a constructor and that SimpleBeanPropertyFilter implements BeanPropertyFilter .







<bean id="productAttributesAndAdvertiserNameFilter" class="org.codehaus.jackson.map.ser.impl.SimpleBeanPropertyFilter" factory-method="filterOutAllExcept">

        <constructor-arg value="name"/>

    </bean>

    <bean id="offerIdFilter" class="org.codehaus.jackson.map.ser.impl.SimpleBeanPropertyFilter" factory-method="filterOutAllExcept">

        <constructor-arg value="id"/>

    </bean>

    <bean id="filterProvider" class="org.codehaus.jackson.map.ser.impl.SimpleFilterProvider">

        <constructor-arg>

            <util:map value-type="org.codehaus.jackson.map.ser.BeanPropertyFilter">

                <entry key="onlyNameFilter" value-ref="productAttributesAndAdvertiserNameFilter" />

                <entry key="onlyIdFilter" value-ref="offerIdFilter" />

            </util:map>

        </constructor-arg>

    </bean>







Any help would be appreciated.


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Comments

  1. Tips For AllJanuary 31, 2012 at 2:48 AM

    Looks like you've found a bug in SimpleFilterProvider.

    I just downloaded the latest sources (1.9.4) and the constructors are defined as such:

    public SimpleFilterProvider() {
    _filtersById = new HashMap<String,BeanPropertyFilter>();
    }

    /**
    * @param mapping Mapping from id to filter; used as is, no copy is made.
    */
    public SimpleFilterProvider(Map<String,BeanPropertyFilter> mapping) {
    _filtersById = new HashMap<String,BeanPropertyFilter>();
    }


    The constructor which takes the mapping ignores it... (i.e. javadoc is incorrect)

    ReplyDelete
  2. Tips For AllJanuary 31, 2012 at 2:48 AM

    I think <util:map> is misplaced here. I'd make it a separate bean, outside of the filter provider declaration, and refer to it. OR I'd change that to a <map> without the util namespace.

    ReplyDelete
  3. Tips For AllJanuary 31, 2012 at 2:48 AM

    I don't see why it is not working.

    At worst, you can create your own class by extending the SimpleFilterProvider and declare this bean in your Spring context...

    ReplyDelete

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