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Find a url in content a site by url it?



I want search into content a site by url it site, if existence my url (for example: http://www.mydomain.com/ ) return it is TRUE else it is FALSE.





If existence url as following list, Return it is FALSE:







- http://www.mydomain.com/blog?12

- www.mydomain.com/news/maste.php

- http://www.mydomain.com/mkds/skas/aksa.html

- www.mydomain.com/

- www.mydomain.com







I want just accsept(find) as(only):





http://www.mydomain.com/ OR http://www.mydomain.com





I tried as:







$url = 'http://www.usersite.com';

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL,$url);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

$contents = curl_exec($ch);

curl_close($ch);

$link="/http:\/\/mydomain.com/";

if(preg_match("/". preg_quote($link,"/"). "/m", $contents) && strstr($contents,"http://www.mydomain.com")){

echo 'TRUE';

} else{

echo 'FALSE';

}







But it doesn't worked, for it what that i want. How can fix it?


Comments

  1. You should not be using preg_quote on your link as it is already in a regex form. Try using the entire regex /http:\/\/mydomain.com/m instead.

    $link="/http:\/\/mydomain.com/m";
    if(preg_match($link, $contents) && false!== stripos($contents,"http://www.mydomain.com")){
    echo 'TRUE';
    } else{
    echo 'FALSE';
    }


    I've also updated strstr to be stripos and to have an absolute comparison as it's not a boolean safe function.

    ReplyDelete

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