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Using jquery to get element"s position relative to viewport



What's the proper way to get the position of an element on the page relative to the viewport (rather than the document).





offsety/x seemed promising:





http://docs.jquery.com/CSS/offset





But that's relative to the document. Is there an equivalent method that returns offsets relative to the viewport?



Source: Tips4all

Comments

  1. Here are two functions to get the page height and the scroll amounts (x,y) without the use of the (bloated) dimensions plugin:

    // getPageScroll() by quirksmode.com
    function getPageScroll() {
    var xScroll, yScroll;
    if (self.pageYOffset) {
    yScroll = self.pageYOffset;
    xScroll = self.pageXOffset;
    } else if (document.documentElement && document.documentElement.scrollTop) {
    yScroll = document.documentElement.scrollTop;
    xScroll = document.documentElement.scrollLeft;
    } else if (document.body) {// all other Explorers
    yScroll = document.body.scrollTop;
    xScroll = document.body.scrollLeft;
    }
    return new Array(xScroll,yScroll)
    }

    // Adapted from getPageSize() by quirksmode.com
    function getPageHeight() {
    var windowHeight
    if (self.innerHeight) { // all except Explorer
    windowHeight = self.innerHeight;
    } else if (document.documentElement && document.documentElement.clientHeight) {
    windowHeight = document.documentElement.clientHeight;
    } else if (document.body) { // other Explorers
    windowHeight = document.body.clientHeight;
    }
    return windowHeight
    }

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