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I'm working on a commercial (not open source) C++ project that runs on a linux-based system. I need to do some regex within the C++ code. (I know: I now have 2 problems.)

I'm trying to parse a plain text document in PHP but have no idea how to do it correctly. I want to separate each word, assign them an ID and save the result in JSON format.

I would like to know if Regular Expressions are Universal for all languages like PHP, Javascript, etc.?

Curly braces in JavaScript regex is used to denote quantifiers. So writing

Given this code: var reg = /a/g; console.log(reg.test("a")); console.log(reg.test("a")); I get this result:

We have an OpenSource Extension Similar like Greasemonkey only used in Firefox . Users can submit (Java)scripts for other Users to run. This gets abused by sending malicious code.

Here is a design though: For example is I put a link such as http://example.com in textarea . How do I get PHP to detect it’s a http:// link and then print it as print "<a href='htttp://example.com'>http://example.com</a>"; I remember doing something like this before however, it was not fool proof it kept breaking for complex links. Another good idea would be if you have a link such as http://example.com/test.php?val1=bla&val2blablabla%20bla%20bla.bl fix it so it does print "<a href='http://example.com/test.php?val1=bla&val2=bla%20bla%20bla.bla'>"; print "http://example.com/test.php"; print "</a>"; This one is just an after thought.. stackoverflow could also probably use this as well :D Any Ideas Source: Tips4all

I would like to replace the following: ="Dark4Red" with =\"Dark4Red\" The = sign and double quotations are fixed ="..." I just need to add slashes before double quotations. $content = preg_replace('/="[^a-zA-Z#0-9]"/', '=\"[^a-zA-Z#0-9]\"', $line); The above solution didn't work. Any idea?

The x modifier code in this tutorial Php regex tutorial gives me the following error: Warning: preg_match() [function.preg-match]: Unknown modifier ' ' in C:\xampp\htdocs\validation\test.php on line 16 Pattern not found What's wrong with it? <?php // create a string $string = 'sex'."\n".'at'."\n".'noon'."\n".'taxes'."\n"; // create our regex using comments and store the regex // in a variable to be used with preg_match $regex =" / # opening double quote ^ # caret means beginning of the string noon # the pattern to match /imx "; // look for a match if(preg_match($regex, $string)) { echo 'Pattern Found'; } else { echo 'Pattern not found'; } ?>

I have a few strings: john doe happy george smith is happy Here's my Regular Expression: ([a-zA-Z ]+) (is happy|happy) I need group 1 to always be a name like "john doe" or "george smith" I need group 2 to always be either "happy" or "is happy" Right now, "george smith is happy" always matches up to "george smith is" and "happy" ... when I really want it to be "george smith" and "is happy" How do I make "is happy" have precedence over "happy"?

I'm developing a js to dig up Bible references on Portuguese web pages, and link them to a youversion.com url. This is one of those pages: http://www.adventistas.org.pt/Evangelismo/Web/Img/Downloads/Trimensario/2012/1t/online/licao7.htm This is the script: http://www.adventistas.org.pt/Evangelismo/Web/Img/Downloads/Trimensario/2012/1t/online/bibleref.js It pretty much works, but it acts kinda funny, and can't find out why. Sometimes it outputs empty links with correct bible references, and then outputs the real link, with a wrong reference. Eg: <a target="_blank" href="http://www.youversion.com/bible/verse/arc/gen/2/1-3" class="passagem"></a> <a target="_blank" href="http://www.youversion.com/bible/verse/arc/gen/2/1-3" class="passagem"></a> <a target="_blank" href="http://www.youversion.com/bible/verse/arc/gen/2/1-3" class="passagem"></a> <

Basically I want to be able to grab the ending of an url, and convert it into a string to be used somewhere. Currently I'm doing this (which is less than optimal): // grab the path, replace all the forward slashes with spaces local_path = location.pathname.toString().replace(/\//g,' '); // strip empty spaces from beginning / end of string local_path.replace(/^\s+|\s+$/g,"")); But I think there is probably a better way. Help? Edit: Could I confidently get rid of the .toString method there?

I am trying to achieve the following for both @ or # . function split(val) { return val.split(/@/); } function extractLast(term) { return split(term).pop(); } Any help really appreciated!

I have some strings like this: 2012-02-05T07:42:47.000Z mixed with other strings. It is always in this format. (but the numbers are not the same, of course...the times are different) (not Sun, 05 Feb 2012 07:42:47 GMT ) I want to know whether a string matches that format. How can I determine that? It's so complicated with the colons and dots and stuff.

Consider the following string: $MRK - Merck - ($AAPL, $MSFT, $F) having day $AA! like $P and me :) Although it's jibberish, it shows my problem. I want to scan for all words starting with a dollar-sign ($) and check them against a pre-defined list of tickers. If there's a match, replace them with a label ({TICKER}), as follows: {TICKER} - Merck - ({TICKER}, {TICKER},{TICKER}) having a day {TICKER}! like {TICKER} an me :) I now use this function: function _process_tickers($string) { $result = db_query("SELECT symbol FROM us_stocks"); while ($row = db_fetch_object($result)) { $tickers[] = ' $' . $row->symbol . ' '; } return str_replace($tickers, ' {TICKER} ', $tweet); } Problem: this only catches tickers that are surrounded by spaces (this $AA is surrounded by spaces) but not other situations like (this ticker has only a space in in front $AA) or (this one is surrounded by commas: my,$AA, ticker). But also two tickers right

I have this regex that test for an input with max length of 5. My problem is I want to exclude the single digit of 2. If string contains only number "2", it should fail. How do I exclude number 2 in this regex? /^([a-zA-Z,\d]){1,5}$/ 13425 - Match 03277 - Match 2 - Fail.

function make_clickable($text) { $ret = ' ' . $text; $ret = preg_replace("#(^|[\n ])([\w]+?://[\w]+[^ \"\n\r\t<]*)#ise", "'\\1<a href=\"\\2\" >\\2</a>'", $ret); $ret = preg_replace("#(^|[\n ])((www|ftp)\.[^ \"\t\n\r<]*)#ise", "'\\1<a target=\"_blank\" href=\"http://\\2\" >\\2</a>'", $ret); $ret = preg_replace("#(^|[\n ])([a-z0-9&\-_\.]+?)@([\w\-]+\.([\w\-\.]+\.)*[\w]+)#i", "\\1<a href=\"mailto:\\2@\\3\">\\2@\\3</a>", $ret); $ret = substr($ret, 1); return($ret); } Problems: http://www.google.com , http://www.google.com ; http://www.google.com . http://www.google.com : http://www.google.com ? (http://www.google.com) as well as make sure that other domains lik

If I had a string with three values that is delimited by spaces, now I want to store these three values in three variables or maybe an array, how to do?

.replace(/([^s]?s)$/, '') I thought [^abc] meant "not any of these characters" but in the code above, it's replacing the s at the end of the word only if there's an s before it. How would I make this regex into: replace the s at the end of the word, only if there's no s before it?

I'm a noob to jquery. Stuck and would appreciate some help. Currently building a tool to grab data from a particular page. The page looks like this: <table width="100%" border="0" align="center" cellpadding="3" cellspacing="1"> <tbody> //This is data group 1 <tr id="parent0"> //Record 1 <td align="left"> <---------- text1 here -------> </td> <td align="left"> <---------- text2 here -------> </td> <td align="left"> <---------- text3 here -------> </td> </tr> <tr id="parent0"> //Record 2 <td align="left"> <---------- text1 here -------> </td> <td align="left"> <---------- text2 here -------> </td> <td align="left"> <---------- text3 here -------> </td> </tr> </tb