The page I am working on has a javascript function executed to print parts of the page. For some reason, printing in Safari, causes the window to somehow update. I say somehow, because it does not really refresh as in reload the page, but rather it starts the "rendering" of the page from start, i.e. scroll to top, flash animations start from 0, and so forth. The effect is reproduced by this fiddle: http://jsfiddle.net/fYmnB/ Clicking the print button and finishing or cancelling a print in Safari causes the screen to "go white" for a sec, which in my real website manifests itself as something "like" a reload. While running print button with, let's say, Firefox, just opens and closes the print dialogue without affecting the fiddle page in any way. Is there something with my way of calling the browsers print method that causes this, or how can it be explained - and preferably, avoided? P.S.: On my real site the same occurs with Chrome. In the ex
we can find city temp by using this find_Location Class. in which firstly find the city location by use by longitude and latitude in android? And after that use the method SendToUrl to find the temperature by use GoogleXML "https://www.google.com/ig/api?weather="
ReplyDeletepublic void find_Location(Context con)
{
Log.d("Find Location", "in find_location");
this.con=con;
String location_context = Context.LOCATION_SERVICE;
locationManager = (LocationManager)con.getSystemService(location_context);
List<String> providers = locationManager.getProviders(true);
for (String provider : providers)
{
locationManager.requestLocationUpdates(provider, 1000, 0,new LocationListener()
{
public void onLocationChanged(Location location) {}
public void onProviderDisabled(String provider){}
public void onProviderEnabled(String provider){}
public void onStatusChanged(String provider, int status,Bundle extras){}
});
Location location = locationManager.getLastKnownLocation(provider);
if (location != null)
{
latitude = location.getLatitude();
longitude = location.getLongitude();
addr=ConvertPointToLocation(latitude,longitude);
String temp_c=SendToUrl(addr);
}
}
}
public String ConvertPointToLocation(double pointlat,double pointlog) {
String address = "";
Geocoder geoCoder = new Geocoder(con,
Locale.getDefault());
try {
List<Address> addresses = geoCoder.getFromLocation(pointlat,pointlog, 1);
if (addresses.size() > 0) {
for (int index = 0; index < addresses.get(0)
.getMaxAddressLineIndex(); index++)
address += addresses.get(0).getAddressLine(index) + " ";
}
}
catch (IOException e) {
e.printStackTrace();
}
return address;
}
private String SendToUrl(String string) {
// TODO Auto-generated method stub
try{
string=string.replace(" ","%20");
String queryString="https://www.google.com/ig/api?weather="+string;
url= new URL(queryString);
conec= url.openConnection();
stream = conec.getInputStream();
xpp = XmlPullParserFactory.newInstance().newPullParser();
xpp.setInput(stream, null);
int eventType = xpp.getEventType();
while(eventType != XmlPullParser.END_DOCUMENT)
{
if(eventType == XmlPullParser.START_TAG)
{String elementName = xpp.getName();
if("temp_c".equals(elementName))
{
int acount=xpp.getAttributeCount();
for(int x=0;x<acount;x++)
{
xpp.getAttributeValue(x);
String str=xpp.getAttributeValue(x);
return str;
}
}
}
eventType = xpp.next();
}
}
My answer is not totally perfect but Yahoo Weather API may help you. This worked perfectly for me.
ReplyDeleteIn this api you have to select one of the City and then you will get weather updates. However you have to go through the source for extracting your portion.
Hope this helps.
There appears to be a full code example on anddev.org google weather api description which should include everything you require.
ReplyDelete