Hi! I have been posted content of ccna1 final exam (latest and only question.) I will post the answer and insert image on sunday. If you care, please subscribe your email an become a first person have full test content. Subcribe now Some question have not content because this question have images content. So that can you wait for me? SUNDAY 1. A user sees the command prompt: Router(config-if)# . What task can be performed at this mode? Reload the device. Perform basic tests. Configure individual interfaces. Configure individual terminal lines. 2. Refer to the exhibit. Host A attempts to establish a TCP/IP session with host C. During this attempt, a frame was captured with the source MAC address 0050.7320.D632 and the destination MAC address 0030.8517.44C4. The packet inside the captured frame has an IP source address 192.168.7.5, and the destination IP address is 192.168.219.24. At which point in the network was this packet captured? leaving host A leaving ATL leaving...
Cisco Certified Network Associate Exam,640-802 CCNA All Answers ~100/100. Daily update
Joshua Weinberg's answer is mostly correct, however the Ox prefix is optional when scanning hexadecimal integers. If you have a string in the format #01FFFFAB, you can still use an NSScanner, but you can simply skip the first character.
ReplyDeleteunsigned result = 0;
NSScanner *scanner = [NSScanner scannerWithString:@"#01FFFFAB"];
[scanner setScanLocation:1]; // bypass '#' character
[scanner scanHexInt:&result];
you can use NSScanner for this
ReplyDeleteint outVal;
NSScanner* scanner = [NSScanner scannerWithString:@"0x01FFFFAB];
[scanner scanHexInt:&outVal];
outVal will contain the int you're looking for. The 0x is optional.
strtol() is your friend.
ReplyDeleteIt converts a string to a long, and you can pass the base of the number in. Strip that # sign off first though, or pass to strtol a pointer to the first numerical character.