Skip to main content

Trying to get value from textbox in column in table



I dynamically created a table with three columns.







<tr>

<td>1</td>

<td>SegName</td>

<td><input type='text' /></td>

</tr>







I'm trying to write a function that goes through each row and grabs the value in that will be in the textbox.





Javascript:







$("#codeSegmentBody").children().eq(x).children().eq(2).val();







The code brings brings up undefined when I do val(), but if I do html it'll grab the html of the textbox.





How can I get this to bring me the value?


Comments

  1. <table id="test">
    <tr>
    <td>
    <input type="text" value="123">
    </td>
    </tr>
    <tr>
    <td>
    <input type="text" value="abc">
    </td>
    </tr>
    </table>

    <script type="text/javascript">
    $(document).ready(function(){

    $("#test").find(":input[type=text]").each(function(){

    alert( $(this).val() );

    });

    });
    </script>


    Here is a fiddle that will get you there:

    http://jsfiddle.net/uS8AK/

    ReplyDelete
  2. Assuming #codeSegmentBody is the name of your table, try this:

    $("#codeSegmentBody td input").each(function() {
    var inputValue = $(this).val();
    alert(inputValue);
    });


    Example fiddle

    ReplyDelete
  3. $("#codeSegmentBody tr input[type='text']").each(function(){
    alert($(this).val());
    })

    ReplyDelete
  4. Try this

    $("#codeSegmentBody tr").each(function() {
    alert($(this).find("input").val());
    });

    ReplyDelete
  5. You are referencing the containing <td> not the input. Try:

    $("#codeSegmentBody").children().eq(x).find(":text").val();

    ReplyDelete
  6. var str = "";
    $("#codeSegmentBody .third-column input").each(function()
    {
    str += this.value;
    });
    alert(str);

    ReplyDelete
  7. Not easier

    $("table tr td input").val();


    ?

    BTW. You don't have any value in this input anyway.

    ReplyDelete

Post a Comment

Popular posts from this blog

Slow Android emulator

I have a 2.67 GHz Celeron processor, 1.21 GB of RAM on a x86 Windows XP Professional machine. My understanding is that the Android emulator should start fairly quickly on such a machine, but for me it does not. I have followed all instructions in setting up the IDE, SDKs, JDKs and such and have had some success in staring the emulator quickly but is very particulary. How can I, if possible, fix this problem?

CCNA 1 Final Exam 2011 latest (hot hot hot)

  Hi! I have been posted content of ccna1 final exam (latest and only question.) I will post the answer and insert image on sunday. If you care, please subscribe your email an become a first person have full test content. Subcribe now  Some question  have not content because this question have images content. So that can you wait for me? SUNDAY 1. A user sees the command prompt: Router(config-if)# . What task can be performed at this mode? Reload the device. Perform basic tests. Configure individual interfaces. Configure individual terminal lines. 2. Refer to the exhibit. Host A attempts to establish a TCP/IP session with host C. During this attempt, a frame was captured with the source MAC address 0050.7320.D632 and the destination MAC address 0030.8517.44C4. The packet inside the captured frame has an IP source address 192.168.7.5, and the destination IP address is 192.168.219.24. At which point in the network was this packet captured? leaving host A leaving ATL leaving...