I have a string like this:
$geometry = "POINT (1.5041909054501184 0.39827301781943014)"
I have to split the two decimal values 1.5041909054501184 and 0.39827301781943014 based on space, into an array. For that, as expected, I have to chop-off 'POINT (' and ')' from the $geometry .
I tried the following lines:
$temp = substr($geometry , strpos($geometry, "(")+1, strlen($geometry)-2);
and
$temp = substr($geometry , strpos($geometry, "(")+1, strpos($geometry, ")")-1);
Echoing $temp in both the cases displays string as:
"1.5041909054501184 0.39827301781943014)"
How can I remove the ')' from the string $geometry ?
UPDATE
How can I generalize it to strings like these?
$geometry = "POINT (1.5041909054501184 0.39827301781943014)";
and
$geometry = "POLYGON ((1.5049088554391572 0.39805485932781448, 1.5049135685638309 0.39805660717232405, 1.5049147247575003 0.39805462248168044, 1.5049101547531727 0.39805287533491257, 1.5049088554391572 0.39805485932781448))";
Try this:
ReplyDelete$str = 'POINT (1.5041909054501184 0.39827301781943014)';
// Remove any character that is not digit, dot or space, then trim whitespace
$stripped = trim(preg_replace('/[^0-9 \.]/', '', $str));
// Split by the space in the middle
$exploded = explode(' ', $stripped);
print_r($exploded);
/*
Array
(
[0] => 1.5041909054501184
[1] => 0.39827301781943014
)
*/
I would just use a regular expression:
ReplyDelete$geometry = "POINT (1.5041909054501184 0.39827301781943014)";
preg_match_all('/POINT \((\d\.\d+) (\d\.\d+)/ ', $geometry, $matches);
$matches[1][0]; // => "1.1.5041909054501184"
$matches[2][0]; // => "0.39827301781943014"
Note that these results are strings, you'll have to cast them to floats to use them as floats.
Maybe better with preg_replace ?
ReplyDelete$geometry = "POINT (1.5041909054501184 0.39827301781943014)";
echo preg_replace('/POINT \((.*?)\)/uis','$1',$geometry);
Well, why not just remove them?
ReplyDelete$geometry = "POINT (1.5041909054501184 0.39827301781943014)";
$temp1 = str_replace("POINT (", "", $geometry);
$temp = str_replace(")", "", $temp1);
Assuming your geometry syntax is always the same, this will do just fine.
Also, since you're starting 7 characters in advance, and you want to chop the last one, give the $length argument a value of length-8:
$temp = substr($geometry , strpos($geometry, "(")+1, strlen($geometry)-8);
Both of these echo correctly.
Edit!
Based on the comments:
Try this one:
$temp = preg_replace("|.+\((.+)\)|", "$1", $geometry);
The third argument to substr is not "end point" but "substring length".
ReplyDeleteSo you need to say:
$start_pos = strpos($geometry, "(")+1;
$temp = substr($geometry , $start_pos , strlen($geometry)-$start_pos);
Then you can use explode to get the two decimals;
list($x, $y) = explode(' ', $temp);
or
$coordArray = explode(' ', $temp);
The 3d parameter should be the length of the substring, not the position in the original string
ReplyDelete